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Student<\/strong> Tutor<\/strong> Student<\/strong><\/p>\n I’m fine but sorta struggling<\/p>\n Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong>:) Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> Tutor<\/strong> Student<\/strong> <\/p>\n Colaboradora: Nicole Rosenstock<\/strong>, Tutora Uruguaya de Biolog\u00eda<\/strong><\/span><\/p>\n","protected":false},"excerpt":{"rendered":" La siguiente sesi\u00f3n muestra un\/a estudiante que presenta un ejercicio t\u00edpico sobre cruzamientos gen\u00e9ticos y predicci\u00f3n de genotipos y fenotipos. Aunque dice haber realizado la primera parte del ejercicio, opt\u00e9 por hacer una correcci\u00f3n de esta parte para asegurarme que los conocimientos te\u00f3ricos y los m\u00e9todos estuvieran claros. Fue aqu\u00ed que descubr\u00ed un error…<\/p>\n","protected":false},"author":9,"featured_media":3600,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"gallery","meta":[],"categories":[92,89],"tags":[],"post_series":[],"_links":{"self":[{"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/posts\/218"}],"collection":[{"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/comments?post=218"}],"version-history":[{"count":1,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/posts\/218\/revisions"}],"predecessor-version":[{"id":3601,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/posts\/218\/revisions\/3601"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/media\/3600"}],"wp:attachment":[{"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/media?parent=218"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/categories?post=218"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/tags?post=218"},{"taxonomy":"post_series","embeddable":true,"href":"https:\/\/dev.latinhire.com\/es\/wp-json\/wp\/v2\/post_series?post=218"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nHelp. I don’t know how to do problem 2 & 3! I think I got the first one done already. 1) Cross a wrinkled-pea, short pea plant with a pure round-pea, tall pea plant. Work the cross on a Punnett square to obtain the F1 generation. Give genotypes ad phenotypes as ratios. (Round and tall are dominant traits. 2) Take any two of the offspring of the above cross (F1) and cross them to obtain the F2 generation. Work the cross on a Punnett square. 3) From the F2 Punnett square you did for the previous question, choose two individuals that will permit you to have a pure strain of winkled-pea, tall pea plants. *If you were looking at the phenotypes, would you be able to be sure you had chosen the correct plants to cross? *How would you know when you have obtained a pure strain of wrinkled-pea, tall pea plants?<\/p>\n
\nWelcome !
\nHow are you?<\/p>\n
\nDon’t worry! We’ll work on this.
\nFirst of all, have you done the 1st part?<\/p>\n
\nI think so<\/p>\n
\nOk, I need some information that is missing there.
\nThere are 2 traits: wrinkle\/pure and tall\/short
\nWhich is dominant in both?<\/p>\n
\noh
\nsorry<\/p>\n
\ndon’t worry :)<\/p>\n
\nround and tall are dominant<\/p>\n
\nI’m asking to check what you’ve done, to see if we can move to the 2nd directly
\nand how did you call the alleles?
\nwhich letter did you use for each one<\/p>\n
\noh I used wrinkled for w
\nshort for r
\nW for round
\nand R for Tall<\/p>\n
\nOk, and how did you write the parental genotypes?
\nwrinkled and short<\/p>\n
\nwr<\/p>\n
\nThat means that it has only one allele for each trait?<\/p>\n
\nround and tall is WR<\/p>\n
\nEach individual receives one allele from father and one from mother
\nright?<\/p>\n
\numm oops
\nyeah<\/p>\n
\nhow would you write the genotypes then?
\nThe logic is the same, just writing the 2 alleles
\nwrinkle and short?<\/p>\n
\nwrinkled short-wwrr<\/p>\n
\nvery good!
\npure round and tall?<\/p>\n
\nround and tall: WWRR<\/p>\n
\nright, let’s assume that is PURE for both traits
\nthat is, it’s homozygous for both
\nright?<\/p>\n
\nyeah<\/p>\n
\nOk, can you do the crossing?
\nin the punnett square, as it asks in the exercise<\/p>\n
\nok<\/p>\n
\nbefore you start…
\noh ok
\nyou did it right
\nPerfect!<\/p>\n
\nand the rest is the same…<\/p>\n
\nvery good
\nhow is this phenotype?
\nremember which is dominant over the other…<\/p>\n
\nit’s the round…<\/p>\n
\ngood…
\nheight?
\ntall or short?<\/p>\n
\nshort…<\/p>\n
\nit’s Rr<\/p>\n
\ni mean tall<\/p>\n
\nright :)
\nSo there you have the F1.
\nThe 1st part of the exercise.
\nLuckily we checked it because if not, there were going to be mistakes
\nin the next part
\nWe have time to do the 2nd part now<\/p>\n
\nok<\/p>\n
\nTake any two of the offspring of the above cross (F1) and cross them to obtain the F2 generation. Work the cross on a Punnett square.
\nYou got the first, I’m sure you can do this, want to try?<\/p>\n
\nummm ok?<\/p>\n
\nWe still have 5 minutes. After that we will have to round up the session, ok?<\/p>\n
\nokType your message here.
\ni dont get it
\nsorry<\/p>\n
\nDOn’t worry
\nLet’s see…
\nSecond part
\nask you to cross to individuals from the F1
\nWe only have one type right?
\nSo we’ll cross 2 \u00abWwRr\u00bb<\/p>\n
\nyeah…<\/p>\n
\nwhich combinations of alleles can this individual give?<\/p>\n
\nummm
\nWW, ww, RR, and rr?<\/p>\n
\nmmm…it has to be one allele for 1 trait and 1 for the other
\nIt has to mix: one allele for height and one for texture<\/p>\n
\nWW, Ww, WR, and Wr?<\/p>\n
\nWhy? WW ?
\nthese are 2 alleles for the same trait
\ndo you agree?<\/p>\n
\noh ok<\/p>\n
\nFrom the genotype:
\nyou take: one allele for the first trait ( W or w) and one for the other (R or r)
\nThe gametes will have half the genotype of the individual<\/p>\n
\nohhhh<\/p>\n
\nand always have alleles for every trait :)<\/p>\n
\nok<\/p>\n
\nso, which are the possible combinations?<\/p>\n
\nWr, wr, WR,<\/p>\n
\nright!<\/p>\n
\nsorry<\/p>\n
\none’s missing<\/p>\n
\nRw?<\/p>\n
\nright
\nso, both individuals will give these 4 combinations<\/p>\n
\nok<\/p>\n
\nand now…the punnett square!
\nOk, fill this.
\nOe we finish with this, we’ll round up the session.<\/p>\n
\nok
\nwait so do i cross those with those with WwRr?<\/p>\n
\nright
\nbut both parents are the same
\nso the combinations are the same
\nyou have to write the same on both sides of the square<\/p>\n
\nok…<\/p>\n
\nThe combinations given by each one are the same :)<\/p>\n
\nam i wrong?<\/p>\n
\nnot at all
\nIt’s perfect
\nNow, the typical crossing.
\nWant to do it now?
\nOr you think you can finish with this?<\/p>\n
\nummm… I think i can finish this myself<\/p>\n
\nOh ok:)
\nProbably you can finish this and the sign back again, to check this and finish the last question, ok?<\/p>\n
\nok
\nthank you<\/p>\n
\nYou’re welcome!
\nGood job!<\/p>\n
\nok bye<\/p>\n
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