La matemática es una ciencia exacta, pero en ocasiones la forma de solucionar problemas en…
Funciones Trigonométricas: Tutoría Online completa con estudiante
Comentarios del Tutor: Elegí esta sesión dado que , a diferencia de la manera en que resolvemos este tipo de problemas en algunas partes de Sudamérica , en EEUU optan por hacerlo utilizando esta «regla» en lugar de emplear la identidad trigonométrica Pitagórica. Además, se utilizan los recursos que se nos sugieren constantemente, chequeo de entendimiento. Un cierre de las sesión adecuado.
Student sec A = -4 , cot B =2/3 with A in QII and B in QIII. Find: Sin 2A cos(A-B) tan B/2 csc A/2
Tutor Welcome! How are you today?
Student im ok. Frustrated
Tutor oh, wellIll help you with this
Student thank you!
Tutor Any ideas about it?
Student I know I will need to use a few different Identities. But im not sure how to find Sin andCos to make them work
Tutor okay , first of all we need to get sin and cos for each angle
let’s think about angle A
Student yes , 1/cos
Tutor right, So how much is cos?
Student -4x?
Tutor we know sec is -4 and you told me sec is 1/cos
so how much is cos?
Student right
Tutor if you have sec you flip it , and you get cos
Student -1/4
Tutor perfect! Now we will use a triangle to get sin
Student i cant believe I didnt get that
Tutor we know cos is adj/hyp right?
Student yes
Tutor so we place the 1 and the 4 , like this…
How can we get the missing side?
Student then solve for b
Tutor yes, how much is it?
great! So how much is sin?
perfect!
Student where did the neg go from cos A
Tutor now we should work on angle B?
sec was negative and we also know the angle is in quad II is negative there
Student oh okay, but we dont nee that on the triangle?
Tutor nope its the same
Student oky
Tutor just think about the quadrant
Student ok
Tutor what about B? Ideas?
Student cot = cos/sin
Tutor right
Student so would cos be 2 and sin be 3?
Tutor [09:43] not exactly you should place the values in the triangle
Student [09:54] ok
Tutor and get the hypotenuse
great!
so , how much is sin B? and cos B?
can we leave a root in the denominator?
Student nope
Tutor so?
great!
let me tell you something angle B, Its in quadrant III, what do we know about the sin and cos values in q III?
Student cos is neg and so is sin
Tutor [15:49] okay, so we place the neg sign for them, now we can get the asked values
Student sin (A+A) is SinAcosA+CosAsinA
Tutor okay , you can plug the values
Student do i include teh negative here?
Tutor yes! How much is that?
Student do they cancel out?
Tutor both are negative
hmmm, you cant do that , you must combine both then you can reduce
Student oh!
Tutor perfect!
Student ok thx
Tutor now let me tell you something we forgot about angle B
Student ok
Tutor its in quadrant III , so what do we know about sin and cos?
Student cos is neg
Tutor and sin?
Student and so is sin
Tutor so we place the neg sign for them
Student i will try the others on my own and log back on if I cannot figure it out
Tutor oh ok great idea!
Student thank you
Tutor Thank you for using our service
Please, do me the favour of completing the survey and comment before leaving
Student yup
Tutor Have a great day! Bye bye
Student bye
Colaborador: Juan Belluscio, Tutor Argentino de Trigonometría